stepen disocijacije kiseline

Submitted by labello on Tue, 06/30/2015 - 14:14
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Opšta diskusija

Izracunati koncentraciju vodonikovih jona u rastvoru sircetne kiseline masene koncentracije 12g/l,ako je stepen disocijacije kiseline 1,4% . Jel' se ovi procenti mnoze sa 100 ?

 

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buduci_student - Tue, 06/30/2015 - 14:23

NE procenti se dijele sa 100

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buduci_student - Tue, 06/30/2015 - 14:25

Imas li resenje zadatka

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buduci_student - Tue, 06/30/2015 - 14:33

C2H4O2-sircetna kiselina

n=m/M

n=12/60=0,2 mol

cj=ce*alfa*Z

cj=0,00112 mol/dm3--->vodonikovih jona

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labello - Tue, 06/30/2015 - 14:34

Resenje je 2,8

 

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labello - Tue, 06/30/2015 - 14:36

Ja dobijem 2,8x10-3

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buduci_student - Tue, 06/30/2015 - 14:39

cj=ce*alfa*Z

cj=0,2*0,0014*1=0,0028=2,8*10-3

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labello - Tue, 06/30/2015 - 14:40

Resenje je 2,8 

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buduci_student - Tue, 06/30/2015 - 14:41

2,8 bi bilo kada bi mnozili ovako

C=0,2*1,4*1

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labello - Tue, 06/30/2015 - 14:48

To je 0.28 

 

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buduci_student - Tue, 06/30/2015 - 15:11

Ma greska je u zbirci