Rastvor

Submitted by Roy Mustang on Tue, 04/29/2014 - 16:02
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Koliko grama 5% rastvor NaOH treba odmeriti da ova kolicina rastvora sadrzi 3.2 g NaCl? :)

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milicaradenkovic - Tue, 05/06/2014 - 11:50

n(NaCl)=m/Mr=3.2/58.5=0.0547 mol

n(NaOH)=n(NaCl)=0.0547 mol

m(NaOH)=n(NaOH)*Mr=0.0547*40=2.188 g

mr=m(NaOH)/w=2.188/0.05=43.76 g 5% NaOH