koliko ima atoma vodonika u 2 dm3 na cetiri stepena?
n(H2)=V(H2)/Vm=2/22.4=0.0893 mol
n(H)=2*n(H2)=2*0.0893=0.1786 mol
N(H)=n(H)*Na=0.1786*6*10(23)=1.072*10(23)
n(H2)=V(H2)/Vm=2/22.4=0.0893
n(H2)=V(H2)/Vm=2/22.4=0.0893 mol
n(H)=2*n(H2)=2*0.0893=0.1786 mol
N(H)=n(H)*Na=0.1786*6*10(23)=1.072*10(23)