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Submitted by haris100 on Mon, 02/16/2015 - 01:50
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Koliko cm3 vode treba dodati na 50 cm3 otopine glukoze, masene koncentracije 2g/dm3 da se dobije otopina cija je koncentracija 0,002 mol/dm3

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milicaradenkovic - Mon, 02/16/2015 - 08:20

c1=y/Mr=2/180=0.011 mol/l

c1*V1=c2*V2

V2=c1*V1/c2

V2=0.011*0.05/0.002=0.277 l

V(vode)=V2-V1=0.277-0.05=0.227 l =227 ml