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dejanbr1's picture

Koliko je cm3 96% H2SO4,gustine 1.84g/cm3 potrebno da bi dobili 106g superfosfata-Ca(H2PO4)2+2CaSO4?

milicaradenkovic's picture

Ca3(PO4)2+2H2SO4---------------------->Ca(H2PO4)2+2CaSO4

n(superfosfata)=ms/Mr=106/234=0.453 mol

n(H2SO4):n(Ca(H2PO4)2)=2:1

n(H2SO4)=2*n(Ca(H2PO4)2)/1=2*0.453/1=0.906 mol

ms=n(H2SO4)*Mr=0.906*98=88.79 g

mr=ms/w(H2SO4)=88.79/0.96=92.49 g

V(H2SO4)=mr/ro=92.49/1.84=50.27 cm3 96% rastvora