Izracunati masu azota

Submitted by Vlaja55 on Tue, 01/21/2014 - 23:57
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Izracunaj masu azota koji se nalazi 500 dm3 vazduha,ako je zapreminski udeo azota 78%

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milicaradenkovic - Wed, 01/22/2014 - 08:36

V(N2)=w*V(vazduha)=0.78*500=390 dm3

1 mol-----------------------22.4 dm3

x mol-------------------------390 dm3

x=390*1/22.4=17.4 mol N2

m(N2)=n(N2)*Mr=17.4*28=487.2 g

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Kimi0603 - Mon, 04/03/2017 - 18:12

Sta je ovo 22.4

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fsd - Tue, 04/04/2017 - 13:49

zapremina 1 mola gasa pri normalnim uslovima (STP)