Koja masa sumpora se nalazi u 1g K2S?
n(K2S)=m/Mr=1/110=0.0091 mol
n(S)=n(K2S)=0.0091 mol
m(S)=n(S)*Mr=0.0091*32=0.2912 g
n(K2S)=m/Mr=1/110=0.0091 mol
n(K2S)=m/Mr=1/110=0.0091 mol
n(S)=n(K2S)=0.0091 mol
m(S)=n(S)*Mr=0.0091*32=0.2912 g