maseni udeo rastvora HNO3
Submitted by mika on Fri, 02/14/2014 - 08:36

Forums:
Koje zapremine 70%rastvora gustine p=1.4 g/cm3 i 20% rastvora nitratne kiseline (HNO3) gustine p=1.1g/cm3 treba pomešati da se dobije 500 cm3 40% rastvora te kiseline?
ro(40 %)=1.2 g/cm3
ro(40 %)=1.2 g/cm3
mru=Vu*ro=500*1.2=600 g
mru=mr1+mr2
600=mr1+mr2
msu=ms1+ms2
w1*mr1+w2*mr2=wu*mru
mr1=600-mr2
0.7*(600-mr2)+0.2*mr2=600*0.4
420-0.5*mr2=240
0.5*mr2=180
mr2=180/0.5=360g
mr1=600-360=240 g
V1=mr1/ro1=240/1.4=171.43 cm3 70 % HNO3
V2=mr2/ro2=360/1.1=327.3 cm3 20 % HNO3