Volumetrija

Submitted by miina123456 on Sat, 02/15/2014 - 18:41
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Opšta diskusija

Nađite volumen koncentrirane HCL gustine 1,19 g/ml , W(HCL)=37% potreban za pripravu 100 ml HCL koncentracije C(HCL)=3 mol/L ?

Ako može postupna izrada zadatka.

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milicaradenkovic - Sat, 02/15/2014 - 19:32

n=c*V=0.1*3=0.3 mol

ms=n*Mr=0.3*36.5=10.95 g

mr=ms/w=10.96/0.37=29.62 g

V=mr/ro=29.62/1.19=24.89 cm3 37 % HCl

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miina123456 - Sat, 02/15/2014 - 20:18

Hvala :)