stehiometrija

Submitted by lejla93 on Sat, 03/01/2014 - 20:16
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izracunati procenat Fe,S,O i H2O u zeljezo(II)sulfatu heptahidratu (FeSO4 * 7H2O)

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milicaradenkovic - Sat, 03/01/2014 - 21:44

FeSO4*7H2O

w(Fe)=Ar(Fe)/Mr=56/2780.201=20.1 %

w(O)=4*Ar(O)/Mr=4*16/278=0.2302=23.02 %

w(S)=Ar(S)/Mr=32/278=0.115=11.5 %

w(H2O)=7*Ar(H2O)/Mr=7*18/278=0.453=45.3 %