Maseni udeo

Submitted by dejanbr1 on Sat, 03/15/2014 - 21:25
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Pri sagorevanju uzorka celika mase 5 g u struji kiseonika dobijen je 0.1 g CO2.Izracunati maseni udeo ugljenika u uzorku celika.

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milicaradenkovic - Sat, 03/15/2014 - 21:46

C+O2----------------------->CO2

n(CO2)=m/Mr=0.1/44=0.0023 mol

n(C)=n(CO2)=0.0023 mol

m(C)=n(C)*Mr=0.0023*12=0.0276 g

w(C)=m(C)/m(celika)=0.0276/5=0.0055=0.55 %