stehiometrija
Submitted by lejla93 on Mon, 03/24/2014 - 20:56

Forums:
koliko tona sumpora mora biti spaljeno da bismo dobili 50 000 m(3) SO2 pri 750mmHg i 80 stepeni C?
koliko tona sumpora mora biti spaljeno da bismo dobili 50 000 m(3) SO2 pri 750mmHg i 80 stepeni C?
S+O2------------------->SO2
S+O2------------------->SO2
n(SO2)=V(SO2)*p/R*T
p=750*133.322=99.99 kPa
n(SO2)=50000*99.99*10(3)/8.314*353.15
n(SO2)=1.703*10(6) mol
n(S)=n(SO2)=1.703*10(6) mol
m(S)=n(S)*Mr=1.703*10(6)*32=54.49 t