Neorganska hemija

Submitted by Vuk Biljuric on Sun, 04/20/2014 - 20:11
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Izracunaj koliko se toplote oslobadja pri gasenju 1kg kalcijum-oksida.deltaH(Ca(OH)2 je-986 kJ/mol,deltaH(Cao)je -636 kJ/mol i deltaH(H20) je -285.8 kJ/mol

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milicaradenkovic - Sun, 04/20/2014 - 21:07

CaO+H2O----------------------->Ca(OH)2

deltaH=deltaH(Ca(OH)2)-deltaH(CaO)-deltaH(H2O)

deltaH= -986-(-636)-(-285.8)= -64.2 kJ/mol

n(CaO)=m/Mr=1000/56=17.86 mol

Q=deltaH*n= -64.2*17.86= -1146.61 kJ