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Submitted by Hemicarka5 on Sat, 04/26/2014 - 19:50
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Pri sagorijevanju uzorka celika mase 5g u struji kiseonika dobijen je 0,1g CO2.Izracunajte maseni udio ugljenika u uzorku celika.

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milicaradenkovic - Sat, 04/26/2014 - 21:31

C+O2------------------------>CO2

n(CO2)=m/Mr=0.1/44=0.00227 mol

n(C)=n(CO2)=0.00227 mol

m(C)=n(C)*Mr=0.00227*12=0.02724 g

w(C)=m(C)/m(celika)=0.02724/5=0.005448=0.5448 %