Gvozdje

Submitted by Hemicarka5 on Sat, 04/26/2014 - 19:57
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Kolika je zapremina 26% sumporne kiseline(ro=1,19 g/cm3) potrebno za rastvaranje 50g gvozdja?

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milicaradenkovic - Sat, 04/26/2014 - 21:43

2Fe+3H2SO4---------------------->Fe2(SO4)3+3H2

n(Fe)=m/Mr=50/56=0.893 mol

n(H2SO4)=3*n(Fe)/2=3*0.893/2=1.3395 mol

m(H2SO4)=n(H2SO4)*Mr=98*1.3395=131.27 g

mr=ms/w=131.27/0.26=504.88 g

V(H2SO4)=mr/ro=504.88/1.19=424.27  cm3 26% kiseline