Organska hemija

Submitted by Vuk Biljuric on Mon, 05/05/2014 - 15:04
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Dibromni derivat cikloalkana sadrzi 70,175% broma.Odrediti molekulsku formulu tog derivata i dati mu naziv. Resenje je C5H10,ciklopentan

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milicaradenkovic - Mon, 05/05/2014 - 16:11

CnH2nBr2

w(Br)=70.175 %

w(Br)=2*Ar(Br)/Mr

Mr=2*80/0.70175=230 g/mol

Mr=2Ar(Br)+n*Ar(C)+2*n*Ar(H)

230=2*80+n*12+2*n*1

230=160+14*n

70=14*n

n=70/14=5 i formula je C5H10.