Zadatak

Submitted by ana123 on Tue, 11/12/2013 - 17:58
ana123's picture
Forums: 
Opšta diskusija

Koliko g hlor etana nastaje adicijom HCl na 2 dm3 etena. Normalni uslovi

milicaradenkovic's picture

milicaradenkovic - Tue, 11/12/2013 - 18:32

CH2=CH2+HCl------------------>CH3CH2Cl

1 mol-----------------------22.4 dm3

x mol------------------------2 dm3

x=2*1/22.4=0.0893 mol etena

n(etena)=n(hlor-etana)=0.0893 mol

m(hlor-etana)=n(hlor-etana)*Mr=0.0893*64.5=5.76 g