cink

Submitted by Tina Trezic on Mon, 06/23/2014 - 15:43
Tina Trezic's picture
Forums: 
Opšta diskusija

koliko miligrama cinka istiskuje 4.48 cm3 vodonika (pod normalnim uslovima) iz hlorovodonicne kiseline (Zn) resenje 13

milicaradenkovic's picture

milicaradenkovic - Mon, 06/23/2014 - 16:11

Zn+2HCl---------------->ZnCl2+H2

n(H2)=V(H2)/Vm=4.48*10(-3)/22.4=0.2*10(-3) mol

n(Zn)=n(H2)=0.2*10(-3) mol

m(Zn)=n(Zn)*Mr=0.2*10(-3)*65=13 mg