Koliko ima atoma vodonika u 5 litara vode na 4 stepena C.
ro(vode)=1 g/ml
m(vode)=ro*V=5000*1=5000 g
n(vode)=m(vode)/Mr=5000/18=277.77 mol
n(H)=2*n(vode)=2*277.77=555.54 mol
N(H)=n(H)*Na=555.54*6*10(23)=3.33*10(26)
ro(vode)=1 g/ml
ro(vode)=1 g/ml
m(vode)=ro*V=5000*1=5000 g
n(vode)=m(vode)/Mr=5000/18=277.77 mol
n(H)=2*n(vode)=2*277.77=555.54 mol
N(H)=n(H)*Na=555.54*6*10(23)=3.33*10(26)