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Submitted by nolenk on Tue, 10/21/2014 - 22:47
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Koliko se grama bazne soli dobija u reakciji 0,3 mola Ca(OH)2 sa odgovarajucom kolicinom H2SO4?

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milicaradenkovic - Wed, 10/22/2014 - 08:16

2Ca(OH)2+H2SO4--------------->(CaOH)2SO4+2H2O

n((CaOH)2SO4=n(Ca(OH)2)/2=0.3/2=0.15 mol

m((CaOH)2SO4)=n((CaOH)2SO4)*Mr=0.15*210=31.5 g