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Submitted by maree_kzs on Wed, 01/07/2015 - 12:40
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Kolika je kolicinska koncentracija(mol/L) koncentrovane sumporne kiseline kod koje je maseni udeo 0.98 a gustina 1,84g/ml?

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milicaradenkovic - Wed, 01/07/2015 - 12:42

c=n/V=ms/Mr*V=mr*w/Mr*V=ro*w/Mr

c=0.98*1.84*10(3)/98=18.4 mol/l

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maree_kzs - Wed, 01/07/2015 - 12:45

HVALA!