alkoholi

Submitted by Saki333 on Tue, 03/17/2015 - 14:54
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Izracunaj maseni udeo propil alkohola u rastvoru koji nastaje kada se 60g 20% rastvora doda 100 g vode?

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jovicjova657 - Tue, 03/17/2015 - 15:40

20g : 100g = x: 60g

x=12g alkohola

a masa rastvora je 100g vode + 60g=160g

w=m(s)/m(r)= 12/160=0,075

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Saki333 - Tue, 03/17/2015 - 18:23

Hvalaaaaa :)