sagorevanje alkohola

Submitted by Maja76 on Tue, 03/17/2015 - 18:27
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Koliko se gasa dobija sagorevanjem 1.5 mola 2-metil-propanola?

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jovicjova657 - Tue, 03/17/2015 - 18:33

CH3-CH(CH3)-CH2OH + 6O2 = 4CO2  + 5H2O

1,5 mol                                      xg

1mol                                         176g

1,5 : x = 1 : 176

x=264g CO2

 

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jovicjova657 - Tue, 03/17/2015 - 18:34

1,5 : x = 1 : 4

x= 6 mola CO2 ako se misli na molove

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Maja76 - Tue, 03/17/2015 - 18:39

Hvala :)

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Maja76 - Tue, 03/17/2015 - 18:40

U pitanju su litri

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jovicjova657 - Tue, 03/17/2015 - 18:47

onda ovako:

1,5 : x= 1 : (4*22,4)

x=134,4 l