zadatak

nolenk's picture

Koliko vode treba pomesati sa 15 g NaCl da bi se dobio 15% rastvor?

jovicjova657's picture

85g

nolenk's picture

Pa uradi mi zadatak.

milicaradenkovic's picture

w(NaCl)=15 %

w=ms/mr

0.15=15/(m(vode)+15)

2.25+0.15*m(vode)=15

0.15*m(vode)=12.75

m(vode)=12.75/0.15=85 g