zadatak

Submitted by nolenk on Fri, 03/27/2015 - 18:42
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Koliko vode treba pomesati sa 15 g NaCl da bi se dobio 15% rastvor?

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jovicjova657 - Fri, 03/27/2015 - 19:05

85g

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nolenk - Fri, 03/27/2015 - 19:10

Pa uradi mi zadatak.

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milicaradenkovic - Fri, 03/27/2015 - 20:42

w(NaCl)=15 %

w=ms/mr

0.15=15/(m(vode)+15)

2.25+0.15*m(vode)=15

0.15*m(vode)=12.75

m(vode)=12.75/0.15=85 g