ph rastvora

Submitted by mali hhemicar on Thu, 06/25/2015 - 16:41
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u 250cm3  rastvora nalazi se 1.5x1018 OH- jona,PH rastvora je?

 

kako ovo postupno resiti

buduci_student's picture

buduci_student - Thu, 06/25/2015 - 16:49

Imas li resenje

buduci_student's picture

buduci_student - Thu, 06/25/2015 - 16:53

9,5 ?

mali hhemicar's picture

mali hhemicar - Thu, 06/25/2015 - 16:55

9 je resenje

 

buduci_student's picture

buduci_student - Thu, 06/25/2015 - 16:57

n=N/Na

n=1,5*10(18)/6*10(23)=0,25*10(-5)

c=n/V

c=0,25*10(-5)/0,25

c(OH)=10(-5)

pOH=5

14=pOH + pH

pH=14-5=9

mali hhemicar's picture

mali hhemicar - Thu, 06/25/2015 - 16:58

da,tako sam i ja,hvala puno

 

buduci_student's picture

buduci_student - Thu, 06/25/2015 - 16:58

Nista :D