stehiometrija

hemija5's picture

Koliko se molova H2SO4  nalazi u 1dm3 96% sumporne kiseline, gustine 1,84 g/cm3?

resenje: 18,02 mol

Acetofenon's picture

C=1840×.96/98=18.02mol/L

V=1L 

n=C×V=18.02mol

milicaradenkovic's picture

n=ms/Mr=mr*w/Mr=ro*V*w/Mr

n=1840*1*0.96/98=18.02 mol H2SO4