Pomoc oko zadatka I

MiaHemija's picture

1.Odredi masu 3%-nog rastvora natrijum-hidroksida koji se utrosi ya potpunu neutraliyaciju 50g 5%-nog sirceta.

milicaradenkovic's picture

CH3COOH+NaOH------------------->CH3COONa+H2O

ms=w*mr=50*0.05=2.5 g CH3COOH

n(CH3COOH)=ms/Mr=2.5/60=0.0417 mol

n(NaOH)=n(CH3COOH)=0.0417 mol

m(NaOH)=n(NaOH)*Mr=0.0417*40=1.668 g

mr=m(NaOH)/w=1.668/0.03=55.6 g 3% rastvora