Analiticka hemija

Submitted by Sofija333 on Mon, 08/28/2017 - 10:00
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Izracunati koliko se grama olovo(II)-sulfata moze rastvoriti u 1 dm3 vode. P(PbSO4)= 1,6 x 10-8 mol2/dm6

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milicaradenkovic - Sat, 09/02/2017 - 13:24

PbSO4----------------->Pb2+ + SO42-

P(PbSO4)=(Pb2+)*(SO42-)

(Pb2+)=(SO42-)=R

P(PbSO4)=R2

R=(koren(P(PbSO4)))=1.27 *10(-4) mol/l

c(PbSO4)=R=1.27*10(-4) mol/l

n=c(PbSO4)*V=1.27*10(-4)*1=1.27*10(-4) mol

ms=n*Mr=1.27*10(-4)*303=0.038 g PbSO4.