Analiticka hemija
Submitted by Sofija333 on Mon, 08/28/2017 - 10:00

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Izracunati koliko se grama olovo(II)-sulfata moze rastvoriti u 1 dm3 vode. P(PbSO4)= 1,6 x 10-8 mol2/dm6
Izracunati koliko se grama olovo(II)-sulfata moze rastvoriti u 1 dm3 vode. P(PbSO4)= 1,6 x 10-8 mol2/dm6
PbSO4----------------->Pb2+ +
PbSO4----------------->Pb2+ + SO42-
P(PbSO4)=(Pb2+)*(SO42-)
(Pb2+)=(SO42-)=R
P(PbSO4)=R2
R=(koren(P(PbSO4)))=1.27 *10(-4) mol/l
c(PbSO4)=R=1.27*10(-4) mol/l
n=c(PbSO4)*V=1.27*10(-4)*1=1.27*10(-4) mol
ms=n*Mr=1.27*10(-4)*303=0.038 g PbSO4.