Peptidi

Submitted by Hemija99 on Wed, 06/13/2018 - 21:46
Hemija99's picture
Forums: 
Opšta diskusija

Koliko ima atoma azota u 0,2mola seril-arginina? Resenje je 6x10*23. 

zlaja99's picture

zlaja99 - Thu, 06/14/2018 - 08:00

H2N-CH(CH2OH)-COOH+H2N-CH[(CH2)2-CH2-N=H-C(NH2)=NH]-COOH---->H20+H2N-CH(CH2OH)CONH-[(CH2)2-CH2-N=H-C(NH2)=NH]-COOH

n(dipeptida)=0.2 mol

N(N)=?

U dipeptidu imamo 5 atoma azota i sad to preracunamo na cestice

N=5*n*Na=0.2*5*6.023*1023=6.023*1023

Pozz