Koliko ima atoma azota u 0,2mola seril-arginina? Resenje je 6x10*23.
H2N-CH(CH2OH)-COOH+H2N-CH[(CH2)2-CH2-N=H-C(NH2)=NH]-COOH---->H20+H2N-CH(CH2OH)CONH-[(CH2)2-CH2-N=H-C(NH2)=NH]-COOH
n(dipeptida)=0.2 mol
N(N)=?
U dipeptidu imamo 5 atoma azota i sad to preracunamo na cestice
N=5*n*Na=0.2*5*6.023*1023=6.023*1023
Pozz
H2N-CH(CH2OH)-COOH+H2N-CH[
H2N-CH(CH2OH)-COOH+H2N-CH[(CH2)2-CH2-N=H-C(NH2)=NH]-COOH---->H20+H2N-CH(CH2OH)CONH-[(CH2)2-CH2-N=H-C(NH2)=NH]-COOH
n(dipeptida)=0.2 mol
N(N)=?
U dipeptidu imamo 5 atoma azota i sad to preracunamo na cestice
N=5*n*Na=0.2*5*6.023*1023=6.023*1023
Pozz