oksido-redukcija

Submitted by marijamarr on Wed, 02/19/2014 - 15:56
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Sredi KMnO4+NH3->KNO3+KOH+MnO2+H2O

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milicaradenkovic - Wed, 02/19/2014 - 17:37

8KMnO4+3NH3--------------------->3KNO3+5KOH+8MnO2+2H2O

Mn7+(+3e-)------------------>Mn4+/2

N+3(-2e-)-------------------------->N5+/3