Procentni racun

Submitted by Kale on Sun, 04/19/2015 - 18:36
Kale's picture
Forums: 
Opšta diskusija

Preradom 495,0 kg antimonove rude dobijeno je 228,5 kg antimona. Izracunaj koliko je % Sb2O3 u rudi?

JOVAN's picture

JOVAN - Sun, 04/19/2015 - 19:40

koje je resenje?

Kale's picture

Kale - Sun, 04/19/2015 - 19:45

Pa nemam resenje :P

JOVAN's picture

JOVAN - Sun, 04/19/2015 - 19:50

valjda ovako treba

mu=495kg

ms=228.5 kg

 

m%= ms/mu x 100

m%=228.5kg/495 kg x 100

m%= 46.16 %

Kale's picture

Kale - Sun, 04/19/2015 - 20:06

Hvala, videcu u skoli da li je tacno :D

jovicjova657's picture

jovicjova657 - Sun, 04/19/2015 - 21:15

to su procenti antimona,a treba da se preracuna na Sb2O3