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Submitted by NikolaM on Wed, 02/19/2014 - 18:29
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Koliki je pH rastvora koji u 200cm3 sadrzi 7,3g HCl-a?

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milicaradenkovic - Wed, 02/19/2014 - 19:00

n(HCl)=m/Mr=7.3/36.5=0.2 mol

c(HCl)=n(HCl)/V=0.2/0.2=1 mol/l

HCl--------------------->H+ + Cl-

{H+}=c(HCl)=1 mol/l

pH= -log{H+}=0