maseni udeo

Submitted by Milica38 on Thu, 02/20/2014 - 11:50
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Opšta diskusija

Izračunati maseni udeo rastvora nastalog mešanjem 100cm3 H2SO4(w=98%, ro=1.84g/cm3) i 200g H2SO4(w=3%)

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milicaradenkovic - Thu, 02/20/2014 - 12:48

mr1=V*ro=1.84*100=184 g

ms1=mr1*w=184*0.98=180.32 g

ms2=mr2*w=200*0.03=6 g

msu=ms1+ms2=180.32+6=186.32 g

mru=mr1+mr2=184+200=384 g

w=msu/mru=186.32/384=0.485=48.5 % H2SO4