rastvori

Submitted by Marija on Thu, 03/06/2014 - 21:28
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koliko vode treba dodati u 200cm3 46%-tne azotne  kiseline gustine 1.28gcm3 da bi se dobio 10%tni rastvor?? hitno

 

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milicaradenkovic - Thu, 03/06/2014 - 22:17

w=10 %

mr=ro*V=200*1.28=256 g

ms=w*mr=256*0.46=117.76 g

mr=ms+m(vode)

m(vode)=mr-ms=256-117.76=138.24 g