puferi

sosa95's picture

U kom molskom odnosu se nalaze CH3COOH I CH3COONA U ACETATNOM PUFERU CIJI JE PH=5?K=2 PUTA 10 NA MINUS 5..DA LI MOZE OBJASNJENJE ZADATKA

Niki1995's picture

H+= K * c(kiselina)/c(soli)
pH=5
H+=10(-5)mol/L

10(-5)=2*10(-5)* c(CH3COOH)/c(CH3COONa)
10(-5)/2*10(-5)=c(CH3COOH)/c(CH3COONa)

1/2=c(CH3COOH)/c(CH3COONa)

 c(CH3COH):c(CH3COONa)=1:2