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Submitted by marank on Thu, 07/03/2014 - 17:23
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Koliko je ml koncentrovane hlorovodonicne kiseline potrebno za pripremanje 3,5 litara rastvora cija ce koncentracija biti 0.770 mol/L?(w=0.38,ro=1.19 g/mol)

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milicaradenkovic - Thu, 07/03/2014 - 17:26

n=c*V=3.5*0.770=2.695 mol

m=n*Mr=2.695*98=264.11 g

mr=m/w=264.11/0.38=695.03 g

V=mr/ro=695.03/1.19=584.06 ml 38% HCl