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Submitted by MilicaP on Sat, 10/25/2014 - 13:36
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Koliko se atoma vodonika nalazi u 112mL amonijaka(normalni uslovi)?

 

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milicaradenkovic - Sat, 10/25/2014 - 13:55

3H2+N2--------------->2NH3

n(NH3)=V(NH3)/Vm=112*10(-3)/22.4=0.005 mol

n(H2)=3*n(NH3)/2=3*0.005/2=0.0075 mol

n(H)=2*n(H2)=2*0.0075=0.015 mol

N(H)=n(H)*Na=6*10(23)*0.015=9*10(21)