vodonik

Submitted by foxy on Sun, 10/26/2014 - 10:41
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koliko je grama vodonika potrebno za redukciju 3,5 grama cistog bakar (II)oksida

 

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milicaradenkovic - Sun, 10/26/2014 - 13:57

CuO+H2------------------->Cu+H2O

n(CuO)=m/Mr=3.5/80=0.04375 mol

n(H2)=n(CuO)=0.04375 mol

m(H2)=n(H2)*Mr=0.04375*2=0.0875 g