Gasni zakoni

Submitted by milospfc95 on Sat, 11/15/2014 - 15:56
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MOZE POMOC OKO OVOG ZADATKA?

KOLIKO SE MOLEKULA NALAZI U 36cm(KUBNIH) VODE NA 277,2K?

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milicaradenkovic - Sat, 11/15/2014 - 16:56

ro(vode)=1 g/ml

m(vode)=ro*V=36*1=36 g

n(vode)=m(vode)/Mr=36/18=2 mol

N(vode)=n(vode)*Na=2*6*10(23)=12*10(23)

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milospfc95 - Sat, 11/15/2014 - 17:34

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