Gasni zakoni

milospfc95's picture

MOZE POMOC OKO OVOG ZADATKA?

KOLIKO SE MOLEKULA NALAZI U 36cm(KUBNIH) VODE NA 277,2K?

milicaradenkovic's picture

ro(vode)=1 g/ml

m(vode)=ro*V=36*1=36 g

n(vode)=m(vode)/Mr=36/18=2 mol

N(vode)=n(vode)*Na=2*6*10(23)=12*10(23)

milospfc95's picture

Hvala