Glicerola

Submitted by amnak0504 on Thu, 04/16/2015 - 20:43
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Koliko se glicerola dobija djelovanjem NaOH na 5 kg palmito-stearo-oleina koji sadrži 4% primjesa 

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milicaradenkovic - Sat, 04/18/2015 - 08:20

Ako ima 4% primesa onda ima 94% palmito-stearo-oleina

m(palmito-stearo-oleni)=m*w=0.94*5=4.7 kg

n(palmito-stearo-olein)=m(palmito-stearo-olein)/Mr=4.7*1000/860=5.465 mol

n(glicerola)=n(palmito-stearo-olein)=5.465 mol

m(glicerola)=n(glicerola)*Mr=92*5.465=502.79 g