Razblazivanje rastvora

dejanbr1's picture

Koliko ima molova u 1 l rastvora dobijenig mesanjem 300 ml rastvora glukoze koncentracije 72 g u litru  i 200 ml rastvora koji u sebi sadrzi 27 g iste supstance?

milicaradenkovic's picture

c1=y1/Mr=72/180=0.4 mol/l

c2=y2/Mr=27/180=0.15 mol/l

n1=c1*V1=0.4*0.3=0.12 mol

n2=c2*V2=0.15*0.2=0.03 mol

nu=n1+n2=0.12+0.03=0.15 mol

Vu=V1+V2=200+300=500 ml=0.5 l

0.15 mol--------------------------0.5 l

x mol---------------------------------1 l

x=0.15*1/0.5=0.3 mol glukoze